Ayende @ Rahien

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Generics Challage: Assert Return Types Matches

I feel that I gave it too much already, and I am giving up. A workaround is too good for this issue.

Given the following class defination:

public class Dog

{

       public static MethodInfo LastCall = null;

       public class BarkInvocation<T>

       {

              public T Bark()

              {

                     LastCall = (MethodInfo)MethodInfo.GetCurrentMethod();

                     return default(T);

              }

       }

 

       public T Bark<T>()

       {

              return new BarkInvocation<T>().Bark();

       }

}

Can you make this print true?

public class Program

{

       [STAThread]

       static void Main(string[] args)

       {

              Dog d = new Dog();

              d.Bark<IList<string>>();

              Type returnType = Dog.LastCall.ReturnType;

 

              List<string> strings = new List<string>();

 

              Console.WriteLine(returnType.IsInstanceOfType(strings));

       }

}

 

Comments

Weex
02/23/2007 01:37 PM by
Weex

IList is not an instance of List, isn't it?

Doug Mayer
02/23/2007 02:22 PM by
Doug Mayer

Wow, this is a good one. The method's return type will always be T, because at runtime it's resolved from System.RuntimeType.

The only way I'd know of is to also have a LastReturnType static field on Dog and set it to typeof(T) in BarkInvocation.Bark()... which I'm sure there's a reason you're not already doing (I know I hate to add what I feel are more fields that aren't required).

@Weex,

If you do a test as I mention above, you'll see that just calling

typeof(IList).IsInstanceOf(new List());

will return true.

Comments have been closed on this topic.